Question

Find the derivative of the function:

y= x^3 / x-1

Answer 1

y = x * 7^(-3x)

y ' = x * ( 7^(-3x) * ln(7) * -3 ) + 7^(-3x) * 1

y ' = -3x * 7^(-3x) * ln(7) + 7^(-3x)

y ' = 7^(-3x) ( -3x * ln(7) + 1 )

Answer 2

i think... i hope that helps.. :)

Answer 3

Answer is y' =2x^3 - 3x^2/ (x-1)^2 but I just don't know how they got that.