Question

A projectile is thrown upward so that its distance above the ground after t seconds is h = - 16t2 + 480t.

After how many seconds does it reach its maximum height?

Answer 1

Take the derivative and find where it is equal to 0.

Answer 2

how do i do that

Answer 3

\[\frac{ dh }{ dt }=-32t+480\]
\[0=-32t+480\]
\[-32t=-480 \rightarrow 32t=480\]
\[t=\frac{ 480 }{ 32 }\]

Answer 4

so the answer would be 15s

Answer 5

yes