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slope of the secant line thru the pts. (4,f(4)) & (9,f(9)) on the graqph of y=f(x) f(x)x^2-7x
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The slope of the secant line is just the average rate of change. You already know how to do it.
oh its the same? okay thanks. ;) again
what about the instantaneous rate of change of y=f(x)
with respect to x at x=4
It's not any different.
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