Help! i must fin x in a triangle where i know one angle and two sides!!!?? it has two sides of 6 and 7 and a 30 degree angle opposite from the side length 6; picture attached

Question

anonymous · Answer

|dw:1361499114701:dw|

directrix · Answer

@thestudentinneed   Just asking, do you have the 30 degree angle located in the right place on the diagram? Adjacent and opposite angles are not the same.

anonymous · Answer

yeah thats how it is on the paper
I'm doing trig if that helps at all

anonymous · Answer

Use the law of sines.  Here, $A,B,C$ represent side lengths with angles $a,b,c$ opposite them.$$\frac{\sin a}{A} = \frac{\sin b}{B} = \frac{\sin c}{C}$$This is a good formula to memorize.

directrix · Answer

> a 30 degree angle adjacent from the side length 6
The diagram shows a 30-degree angle OPPOSITE a side of length 6.

directrix · Answer

You're working with the ambiguous case so there may be zero, one, or two solutions.

anonymous · Answer

oh sorry so i typed it wrong but i still have no clue

anonymous · Answer

how do i put in the different numbers to solve it though? @yakeyglee

directrix · Answer

I you typed the problem wrong, my suggestion is to close this thread and open a new one with the correct information. It's your call, though.

anonymous · Answer

i just fixed it

anonymous · Answer

You could take $A=6$, $B=7$, $a=60^\circ$, and $b=x$.

anonymous · Answer

CORRECTION: $\color{red}{a=30^\circ}$

anonymous · Answer

okay thanks ill try that

anonymous · Answer

alright so far this is what i have|dw:1361502130124:dw|