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Biology 22 Online
OpenStudy (ksaimouli):

simplyfy

OpenStudy (ksaimouli):

how to get ln2 from that

OpenStudy (ksaimouli):

@zepdrix

OpenStudy (ksaimouli):

\[\int\limits_{\pi/6}^{\pi/2}\cot x dx\]

OpenStudy (ksaimouli):

i know that cotx =ln sinx +c

zepdrix (zepdrix):

The integral of cotx? Ok good c:

OpenStudy (ksaimouli):

which will givw me ln1-ln(1/2)

OpenStudy (ksaimouli):

0-ln(1)-ln(2) gives me -ln2 but the book gives ln 2

zepdrix (zepdrix):

\[\large \ln (a)-\ln(b)=\ln\left(\frac{a}{b}\right)\]

zepdrix (zepdrix):

where is the 0- coming from? :o

OpenStudy (ksaimouli):

ln(1)=0

zepdrix (zepdrix):

Oh you were doing something fancy, hmm

OpenStudy (ksaimouli):

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