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y=f(t)=-16t^2+50t+34 a) how high above the ground is the bridge in feet? b) What is the average velocity of the ball in for the first second? c) Decide at what time, t, the ball reaches its maximum height. Round the answer to one decimal place.(in seconds)
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is y describing the position of the ball
if it is. for a, the height of the bridge will be the ball's position when t is 0
yea y is the position of the ball
for c) you can take the derivative of y and set that equal to zero to find the max position
do those two answers make sense
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can you get b) by yourself
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