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What is the solution of 16^(x-2) = 2^2x? A. 4 B. 2 C. 3/4 D. -2
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What power of 2 is 16?
4, I think?
Right. \[(2^{4})^{(x-2)}=2^{2x}\] Now you're down to rules of exponents. What is the simplification of the left side?
That's what I don't know. /:
OK. \[(a ^{c})^{d}= a ^{c \times d}\] Use that rule on the left side.
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