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Defferentiate y = e^4x cosx
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e^4xcosx * (4cosx - 4xsinx)
Answer is -e^4x sinx + 4e^4x cosx but i'm still confused.
but y r u confused
okay i think i get it better now. so, u = e^ 4x u' = 4e^4x, v = cosx, v' = -sinx then I use u'v +v'u?
yes
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Does it matter if i have it backwards? like 4e^4x cos-e^4x sinx instead of -e^4x sinx + 4e^4x cosx?
no
Okay. Thanks!
mention not
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