Question

PLease help me with this i am having soo much truble with it
A family is having a pool built in their backyard. If their yard is rectangular and measures 7x by 6x and the pool is circular with a radius of 2x how much of the yard will be left over after the pool is built?
38x2
42x2 – 4x2
42x2 – 2x2
38x2

Answer 1

hmm... looks like the answer is neither of those choices.... the answer should be in terms of pi....

Answer 2

those are the answer choices..

Answer 3

ok... sorry i can't help...

Answer 4

this lesson is over
Polynomials and Factoring

Answer 5

ok its fine it confused the crap outta me lol

Answer 6

just to close it out,
Area left over = Area of Rectangle - Area of Circle

Area of rectangle = (7x)(6x) = \(\ 42x^2 \)
Area of circle = \(\ \pi \cdot r^2=\pi (2x)^2=4\pi x^2 \)

so
Area left over = \(\large 42x^2-4\pi x^2 \)

Answer 7

thx lol i thought you couldnt help?

Answer 8

i couldn't help with the answer choices but i can actually help in solving the problem...

Answer 9

Can you help with these too?


A sports team is building a neW stadium on a rectangular lot of land. If the lot measures 6x by 10x and the sports field will be 1x by 4x, how much of the lot will be left over to build bleachers on?
56x2
64x2
30x2
60x2
Simplify the product using the distributive property.

7. (5h – 3)(3h + 7)
15h2 – 44h + 21
15h2 – 26h – 21
15h2 + 44h + 21
15h2 + 26h – 21

Answer 10

for the first one, just subtract....
Whole Field = (6x)(10x) = ???
Sports Field = (1x)(4x) = ???
Bleachers = Whole Field - Sports Field = ???

for #7, do you know FOIL ???

Answer 11

no lol whats foil?

Answer 12

and for the first one idk how to subtact those.

Answer 13

FOIL : First, Outside, Inside, Last