Question

1 + sec2x sin2x = sec2x

Answer 1

verify the trigonometric equation by substituting identities.

Answer 2

no its 1+(1/cos2x)(sin2x)(cos2x)

Answer 3

its is 1+sin2x

Answer 4

no, the question the they are asking me is what i posted

Answer 5

1 + sec^2(x)*sin^2(x)

=> 1 + [1/cos^2(x)]*sin^2(x)

=>1 + sin^2(x) /cos^2(x)

=> 1 + tan^2(x)

=> sec^2(x)

Answer 6

thank u

Answer 7

np