Question

An acute angle θ is in a right triangle with sin θ =8/9 . What is the value of cot θ?

Answer 1

help meeee!!!

Answer 2

first find x

Answer 3

by solving

x^2 + 8^2 = 9^2

Answer 4

@jim_thompson5910 is it sqrt(17)/9 ??

Answer 5

x^2 + 8^2 = 9^2

x^2 + 64 = 81

x^2 = 81 - 64

x^2 = 17

x = sqrt(17)

Answer 6

so you were close

Answer 7

cot(theta) = adjacent/opposite

Answer 8

@jim_thompson5910 ahh so sqrt(17)/8??

Answer 9

you got it

Answer 10

thank you!!!!!!!!!!!!! <333

Answer 11

you're welcome

Answer 12

and how odd...when i drew the square root above, it looked good

now the 17 is overlapping the square root symbol

but that's ok i guess