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HELP! :) What is the 9th term of the geometric sequence where a1 = 1024 and a3 = 64?
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0.015625 0.0625 0.125 0.25
I think its A? :)
geometric seequence means : \[a_n=q^{n-1}a_1\] so \[\frac{a_3}{a_1}=q^2=\frac{64}{1024}=1/16\] so q=1/4 now: \[a_9=(1/4)^81024=0.015625\]
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