Question

Did I do these 2 problems correctly?

log3 (3x+8)=log3 (x^2+x)
3x+8=X^2+x
-x^2+2x+8
(x-4)=0 or (-x+2)=0
x=4 or x=-2
*I then plugged in the numbers to the equation*
Final Answer: x=4 or x=-2



log7 (x^2-4) = log7 (-x+2)
x^2-4=-x+2
x^2-6=0
(x-3)=0 or (x+2)=0
x=3 or x=-2
*I plugged in the numbers into the equation*
Final Answer: EXTRANEOUS SOLUTION