Question

expand each product
(2x-7)(3x+8)

Answer 1

Use the foil method - First Outer Inner Last
\[(2x-7)(3x+8)\]
2x*3x first,\[6x^2\]
2x*8 second\[16x\]
-7*3x next\[-21x\]
-7*8 last equals
-56
the full version : \[6x^2 + 16x - 21 x - 56\]
combine like terms
answer:
\[6x^2 -5 x - 56\]