Question

c^2-13=0
The furthest I can go is =/-√13
Am i missing something?

Answer 1

\[c^2-13=0\]\[c^2=13\]\[c=+/-\sqrt{13}\]

Answer 2

Clarifying that you have c=+/-sqrt(13)
No you're fine. 13 is prime so not much else you can do.

Answer 3

good job.

Answer 4

Alright I got IT!!!! Thank you guys