Question

a broken clover has 2 leaves, a normal clover has 3 leaves, and a lucky clover has 4 leaves. in a bunch of these clovers, there are twice as many normal clovers as broken clovers and 5 times as many normal clovers as lucky clovers. the bunch has a total of N leaves. N is greater than 200. what is the least value of N?

Answer 1

If X = number of broken clovers

2X + 2 (3X) + 2/5 (4X) = N

10X + 30X + 8X = 5N

48X = 5N

X = 5N / 48

Possible N = 5 x 48 = 240

X = 5 x 5 = 25

Answer X = 25

Answer 2

the question is to find of the value of N not X, so the answer is N=240?

Answer 3

but thank you for your help

Answer 4

yr welcome but do u get this

Answer 5

just stil confusing

Answer 6

srry but not at my skill

Answer 7

ok i will ask to other members
@jim_thompson5910

Answer 8

@kropot72

Answer 9

pooja195 is correct

You want to make x = 5N/48 equal to some integer


200/48 = 4 remainder 8

so 192/48 = 4 remainder 0 (subtract 8 from 200 to get 192)


Now add 48 to 192 to get 192+48 = 240

This is the smallest value of N possible to make 5N/48

So that's why the answer is 240

Answer 10

*to make 5N/48 an integer

Answer 11

thank you sir!

Answer 12

np