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sin[inverse tan(-6)] exact answer
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arcsin(tan(-6)) ??
|dw:1361679029675:dw|
Should be -6 actually
@abb0t what does that mean? i need to solve for the exact value.
|dw:1361679072991:dw|
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I believe it's \(\sin(\tan^{-1}(-6))\) Since \(-6\) isn't typically an angle.
would it be -6/sqrt (35)
What's \(36^2+1^2\)?
woops, ignore that 3
anyway, you're close.
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37
then take the sqrt ?
yeah
ok so -6/sqrt(37)?
yeah
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thanks (: i might have a few more trig questions in a few mins.
Just draw the triangle and remember SOH CAH TOA
ok (: thanks
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