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factor 9a^3-15a^2+3ab-5b. A) (3a-5)(3a^2-b) B)(3a+5)(3a^2+b) C)(3a+5)(3a^2-b) D)(3a-5)(3a^2+b)
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Factor the first two terms: 3a²(3a-5). Factor the last two terms: b(3a-5). You now have: 3a²(3a-5)+b(3a-5). There are only two terms left. If you factor out the common factor, you have the answer!
is the answer 3a-5 and 3a^2-b?
No, because 3a²(3a-5)+b(3a-5) = (3a²+b)(3a-5), I'd say it is 3a-5 and 3a²+b
o okay now i understand, thank you
You're welcome!
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