Question

Find the vertex and axis of symmetry of the graph of the function ..... F(x) = x^2 + 4x + 3

Answer 1

the axis of symmetry is found for for a parabola in the general form

\[y = ax^2 + bx + c\]

by using the formula

\[x = \frac{-b}{2a}\]

the vertex will be

\[(\frac{-b}{2a}, f(\frac{-b}{2a}))\]

in your question a = 1 and b = 4

Answer 2

thank you!