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At a golf tournament, a golfer hits a ball on the fairway, launching it at an angle of 37° to the horizontal. Given that the ball's flight time is 4.8 seconds: a) calculate it's initial velocity b) calculate it's horizontal range I thought that you have: a = -9.8 m/s² Δt = 4.8 s Δdy = 0 m I used the equation Δdy = v1yΔt + 1/2aΔt² to figure out v1y but I'm not sure if I'm on the right track.
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