Question

tan x (csc x + 2) = 0

Answer 1

\[\tan x=0\\
\text{and}\\
\csc x+2=0\]
\[x=\tan^{-1} 0\\
\text{and}\\
\csc x=-2\]
\[x=\tan^{-1} 0\\
\text{and}\\
\sin x=-\frac{1}{2}\]
\[x=\tan^{-1} 0\\
\text{and}\\
x=\sin^{-1}\left(-\frac{1}{2}\right)\]
Think you can figure those out?

Answer 2

Think so, give me a second

Answer 3

Got it, thank you very much!