Question

3 sin x=2 cos^2 x solve

Answer 1

try like this:
since cos^2x=1-sin^2x
3sinx=2(1-sin^2x) or
2sin^2x+3sinx-2=0
now let sinx=t, then
2t^2+3t-2=0 and solve for t. Later you will have to find corresponding values of x

Answer 2

thanks!

Answer 3

yw