Question

the ends of a base of an isosceles triangle are (-3,3) and (-4,4) and the length of each of the other sides is 13. find the coordinates of the third vertex

Answer 1

@zepdrix

Answer 2

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Answer 3

\[\large d_1=\sqrt{(x+3)^2+(y-3)^2}\]\[\large d_2=\sqrt{(x+4)^2+(y-4)^2}\]And we know that,\[\large d_1=d_2\]