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Solve the following system of equations algebraically for ALL values of x and y. y=x^2+2x-8 y=2x+1
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Before you start, can you think of how many x-values possibly are solution of this system?
3?
there are 2 solutions to x, since it is squared.
ok what do i do next?
try and eliminate one variable. y is the easiest to eliminate since you have two equations for y
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ok now i have 0=x^2-9
factor that.
x= 3 or -3
yes....y should be very easy to find now
y=0?
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y = 2x +1 plug in the values of x that you found
y=7
there are 2 solutions to y since there are 2 solutions to x.
y=7 and y=-7
no.... y = 2(3) + 1 = 7 y = 2(-3) + 1 = -5
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oh ok thanks
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