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Physics 12 Online
OpenStudy (anonymous):

A 15 g stone is tied to the end of a string and moves in a horizontal, circular path. The radius of the circle is 1.0 m. The stone makes 35 complete revolutions in 20 s. What is the tension in the string?

OpenStudy (anonymous):

Then tension gives the stone the required centripetal force What is the expression for centripetal force?

OpenStudy (anonymous):

\[F_C=\frac{ mv^2 }{ r }\]

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