Question

Got another i cannot seem to Algebra correctly any help is appreciated.

(.3-X)^2\(.2+X)=.180

Answer 1

\[\frac{(0.3-x)^2}{(0.2+x)}=0.180\]\[ 0.180(0.2+x)=(0.3-x)^2\]Distribute and solve

Answer 2

right, so far ive done .036+ .18x = .09 -.6x +x^2 when i solve from ehre i get
\[x^2 -.6x +.09= .036 +.18x \]

then
-.036 -.18x from both sides give \[x^2 -.42x +.054\]

Answer 3

when i apply the quadratic to this equation it gives an unreal answer for both + and - i cannot have an unreal... i have to be making a mistake but ive ran through around 4 times so far

Answer 4

http://www.wolframalpha.com/input/?i=%28.3-x%29^2 \%28.2%2Bx%29%3D.180

Answer 5

-.6x - 0.18x = - 0.78x

Answer 6

just got it thanks again,