integrate by partial fractions

2/2x^2+3x+1
=2/(2x+1)(x+1)
=2/(2x+1)(x+1)=(A/2x+1)+(B/x+1)
=2=A(x+1)+B(2x+1)
let x =-1
2=B(-1)
B=-2
Now, let x=-.5
2=A(.5)
4=A

am i doing something wrong where, i still cant seem to get the answer in the book

Question

integrate by partial fractions

2/2x^2+3x+1
=2/(2x+1)(x+1)
=2/(2x+1)(x+1)=(A/2x+1)+(B/x+1)
=2=A(x+1)+B(2x+1)
let x =-1
2=B(-1)
B=-2
Now, let x=-.5
2=A(.5)
4=A

am i doing something wrong where, i still cant seem to get the answer in the book

anonymous · Answer

well. just got the right answer after 30 minutes. ._.