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1213: how many permutations can be made when the number formed must be greater than 2000
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Well, It is clear that the first number has to be either 2 or 3 so we have 2 choices for the first number. Then we have 3 choices for the second number, 2 choices for the third number and 1 choice for the fourth number so: 2(3)(2)(1)= 12
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