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2cos^(2)θ-cosθ=1
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I really think that you should take a long moment to just learn your trig identities. Lol.
Lol, eventually getting the hang of it...slowly
Anyways, \[2\cos^2(\theta)-\cos(\theta)-1 = 0\]
Oh gosh, I just factored a bit too early. I factored cos out: cos(2cos(x)-1)=1. I see my problem, thanks.
Did you get: (cos x -2) (cos x +1)?
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Oh nvm, forgot to bring back to the 2. My mistake :/
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