Ask your own question, for FREE!
Mathematics 25 Online
OpenStudy (anonymous):

2cos^(2)θ-cosθ=1

OpenStudy (abb0t):

I really think that you should take a long moment to just learn your trig identities. Lol.

OpenStudy (anonymous):

Lol, eventually getting the hang of it...slowly

OpenStudy (abb0t):

Anyways, \[2\cos^2(\theta)-\cos(\theta)-1 = 0\]

OpenStudy (anonymous):

Oh gosh, I just factored a bit too early. I factored cos out: cos(2cos(x)-1)=1. I see my problem, thanks.

OpenStudy (anonymous):

Did you get: (cos x -2) (cos x +1)?

OpenStudy (anonymous):

Oh nvm, forgot to bring back to the 2. My mistake :/

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!