The potential energy between two toms(in a molecule) is given by..
U(x)=a/x^12-b/x^6..
where a & b=+ve and x=distance b/w 2 atoms..The molecule is in stable equilibrium when x=?
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OpenStudy (dls):
\[\LARGE (ax^{-12} -bx^{-6})\]
2nd derivative=minimum
\[\LARGE \frac{156}{x^{14}}-\frac{42b}{x^8}<0\]
if im going right
OpenStudy (dls):
2nd derivative=negative*
OpenStudy (shubhamsrg):
whats the need?
body will be in eqbm when net force on it = 0
OpenStudy (shubhamsrg):
F= -dU/dx
OpenStudy (dls):
yes
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OpenStudy (shubhamsrg):
So just make the substituion.
OpenStudy (dls):
Diff U?
OpenStudy (dls):
once?
OpenStudy (shubhamsrg):
no, diff yourself! >.<
OpenStudy (shubhamsrg):
yes once
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OpenStudy (dls):
\[\LARGE -12ax^{-13}+6bx^{-7}\]
OpenStudy (dls):
=F
OpenStudy (shubhamsrg):
=-F
OpenStudy (shubhamsrg):
it doesn;t matter, just put that =0
OpenStudy (dls):
0?
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OpenStudy (shubhamsrg):
net force =0
OpenStudy (dls):
that is neutral eqm?
OpenStudy (dls):
net force=-ve is stable eqm
OpenStudy (shubhamsrg):
hein ?
OpenStudy (shubhamsrg):
just put that 0, >.<
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OpenStudy (dls):
\[\LARGE x=\sqrt[7]{\frac{2a}{b}} \]
nice
OpenStudy (dls):
6*
OpenStudy (shubhamsrg):
:)
OpenStudy (shubhamsrg):
now lets dance? :)
OpenStudy (dls):
but why 0
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OpenStudy (shubhamsrg):
celebration time!
OpenStudy (shubhamsrg):
I can sing also, I know tinku jiya song :)
OpenStudy (dls):
.-.
OpenStudy (shubhamsrg):
pal pal na maane.. ??
OpenStudy (dls):
go back where you came from right now :P
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OpenStudy (shubhamsrg):
my space ship left me! :(
I am right now staying with rohit.
OpenStudy (shubhamsrg):
please complete the song, pal pal na maane.. ?
OpenStudy (dls):
\[\LARGE \rho hit ?\]
OpenStudy (shubhamsrg):
phuck ?
OpenStudy (dls):
D:
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