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Explain, in complete sentences, how you would factor 2x^8 + 44x^4 + 242 i already got to this part 2(x^8+22x^4+121) someome please explain to me what the next step is?
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The way i would solve this question is use the method of substitution then solve it quadratically, then refer it back to its original state
so you need to let x^8=m^2, so x^4=m
can you facator u^2 + 22u +121 ? with u= x^4
2(m^2 +22m + 121)=0
now 2(m+11)^2=0
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so m=-11
therefore x^4=-11, and x^8=121
have you done complex numbers?
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