Question

6sqrt(x)(x^3-8sqrt(x)+7)
findf'(9)=

Answer 1

\[f(x)=6\sqrt{x}(x^3-8\sqrt{x}+7)\]

Answer 2

@stamp

Answer 3

Take the derivative. Distribute the \[6\sqrt x \]to obtain\[6x^{7/2}-48x+42\sqrt x\]Take the derivative of each term.

Solution: http://www.wolframalpha.com/input/?i=derivative+of+6x%5E.5%28x%5E3-8x%5E.5%2B7%29

Then evaluate f'(x) for f'(9).

Answer 4

f'(9) = http://www.wolframalpha.com/input/?i=-48%2B21%2Fsqrt%28x%29%2B21+x%5E%285%2F2%29+%2C++x%3D9