Ask your own question, for FREE!
Mathematics 23 Online
OpenStudy (anonymous):

What is the value of x in the parallelogram below? (Picture below.)

OpenStudy (e.cociuba):

Where is the x?

OpenStudy (anonymous):

OpenStudy (anonymous):

Sorry, I posted the wrong picture before.

OpenStudy (e.cociuba):

its kool

OpenStudy (anonymous):

2x+16=140 and solve for x

OpenStudy (e.cociuba):

The value of x=44

OpenStudy (anonymous):

x=62?

OpenStudy (anonymous):

that's what i got

OpenStudy (e.cociuba):

No u subtract 16 from 140 then divide by 2

OpenStudy (e.cociuba):

to get 44

OpenStudy (e.cociuba):

i mean 104

OpenStudy (e.cociuba):

srry mistake:)

OpenStudy (anonymous):

2x+16=140 -16=140-16 2x=124/2 x=62

OpenStudy (anonymous):

thanks adri!

OpenStudy (e.cociuba):

its 104 NOT 140!!

OpenStudy (anonymous):

you're welcome

OpenStudy (e.cociuba):

u did a mistake

OpenStudy (e.cociuba):

Its 2x+16=104 NOT 2x+16=140

OpenStudy (anonymous):

oh sorry 2x+16=104 2x=104-16 2x=88 x=44

OpenStudy (anonymous):

OH RIGHT! I totally missed that. In that case, x=44

OpenStudy (e.cociuba):

yup:) thts wat i said from the beginning! its kool though:)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!