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Mathematics 16 Online
OpenStudy (anonymous):

What is the value of x in the parallelogram below? (Picture below.)

OpenStudy (anonymous):

OpenStudy (anonymous):

@e.cociuba

OpenStudy (anonymous):

4x-20+61=180 4x=139 x=139/4

OpenStudy (anonymous):

thanks!

OpenStudy (e.cociuba):

np:)

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