Question

Find each square

1) (w-12)^2
2)(b-5)^2
3)(6x-8)^2
4)(9j-2)^2
PLEASE HELP :)

Answer 1

All of them follow the same pattern.
(a - b)^2 = a^2 - 2ab + b^2

I'll do the first one as an example.
In your first problem above you have (w - 12)^2. You are squaring w - 12. The first term of w - 12 is w, and the second term is -12.
Square the first term and place it on the left.
w^2
Then take the first term times the second term times 2 and write it down:
w * (-12) * 2 = -24w, so now you have
w^2 - 24w
Then square the second term and write it down:
w^2 - 24w + 144
That is it.
Now try the others. If you need help, ask, but try it first.

Answer 2

Thank you the expalining was great -)