Question

4sin(2θ)-2cos(θ)=0

Answer 1

hi there ok we will apply the sum of angles identity to solve this problem

Answer 2

\[4(2\sin(\theta)\cos(\theta))-2\cos(\theta)=0\]

Answer 3

So far, I have that. Just stuck at that part

Answer 4

\[8\sin(\theta)\cos(\theta)-2\cos(\theta)=0\]

Answer 5

\[2\cos(\theta)[4\sin(\theta)-1]=0\]

Answer 6

so either\[2\cos(\theta)=0\]
or \[4\sin(\theta)-1=0\]

Answer 7

can you do the rest?

Answer 8

Yes, got it. Thank you very much :)

Answer 9

your more than welcome...