Explain, in your own words, the step-by-step process to simplifying the expression below. Include the simplified answer in your explanation. (6x2 − 5) − (3x2 + x + 7)
can u tell me what the 6x2 and the 3x2 mean?
is it 6 times 2 and 3 times 2? @Solmyr
I thought it was 6x^2 and 3x^2 ??
yup
distribute the - through the parenthesis.
ok srry @ChelseaSweets i was afk
what is afk ?
whats afk?
away from keyboard
lol....ok
do you know how to distribute the - through the parenthesis ?
sadly no
Oh haha, thats fine dude
im srry to say but i have to be quick with this
ok.....if you just have a sign, like a - or a + with no number by it, the number becomes a 1. So, you have -1(3x^2 + x + 7)...when I say distribute, I mean multiply the -1 by everything in that parenthesis. Can you do that ?
bout to hit the hay for the night
ok so first do i need to work the problem out in the parenthesis then multiply??
6x^2 - 5 - 3x^2 - x - 7 (combine like terms) 3x^2 - x - 12 <---answer
by multiplying by the -1, it changed everything in parenthesis to negatives. That got rid of the parenthesis. Then I just combined like terms. Do you understand ?
ok but just to show the work 6x^2 - 5 - 3x^2 - x - 7 -3 -3 +7 +7 3x^2 - x - 2 multiply -1 3x^2 - x - 12
where are you getting the -2 ?
(6x2 − 5) − (3x2 + x + 7) ok so multiply everything in the parenthesis by -1 6x^2 - 5 - 3x^2 - x - 7 combine like terms 3x^2 - x - 12
srry i understood it wrong the first time
let me show you about combining like terms... 6x^2 - 3x^2 = 3x^2 there is only on x and it is -, so that is -x -7 - 5 = - 12 That leaves you with 3x^2 - x - 12
Do you understand how I multiplied the -1 through the parenthesis to get rid of the parenthesis ?
ok i understand now
not sure about the -1 though
6x^2 - 5 - (3x^2 + x + 7) to get rid of the parenthesis, you have to multiply everything in the parenthesis by a -.....which is the same as a -1. 6x^2 - 5 -1(3x^2 + x + 7) 6x^2 - 5 (-1)3x^2 (-1)x (-1)7 6x^2 - 5 - 3x^2 - x - 7 combine like terms... 3x^2 - x - 12 Does that help ?
yes it does thank you for the help
you are welcome :)
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