Question

log(3x+1)=2 @jim_thompson5910 i'll show you the work

Answer 1

base it,

so it is 10^log(3x+1) = 10^2
the 10^log(base 10) cancels because they are inverse functions and thus you are left with:
3x+1=100
3x=99
x=33

If you want to check, punch in
log(3*33 +1)
log100=2

Answer 2

Thank you very much that was very helpful =) @pooja195

Answer 3

no problem