Question

How would you solve for the missing probability?
X 0 1 2 3 4 5 6
P(X) .0821 .2052 .2565 ? .1336 .0668 .0278

Answer 1

Are there no other possible values? If so, the sum of the probabilities must be unity (1.0000).

Answer 2

P(X = 3) = 1.0000 - (0.0821 + 0.2052 + 0.2565 + 0.1336 + 0.0668 + 0.0278)

Answer 3

I keep getting .228, is this right? The key said that the answer was .214

Answer 4

With the values given in your question you are getting the correct answer.