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Find the limit: Lim (x^3)-9x/x-3 x->3
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\[\lim_{x \rightarrow 3}x ^{3}-9x \div x-3\]
\[\frac{x^3-9x}{x-3}=\frac{x(x^2-9)}{x-3}=\frac{x(x+3)(x-3)}{x-3}=x(x+3)\]
replace \(x\) by \(3\) for your answer
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