Question

find the dy/dx of y=10^logx

Answer 1

\[\log x = \log_{10} x\], is it true?
If so, y=x, then dy\dx=1, for x>0

Answer 2

Take natural log of both sides.
Implicitly differentiate \((\ln(y))' = y'/y\).
Substitute back in \(y=10^{\log(x)}\)