Question

how do I find the derivative of y = sec^-1(t+1)

Answer 1

do you know what the derivative of arcsecant is?

Answer 2

isn't it 1 / absolute value of x times the square root of x^2 -1

Answer 3

yes

Answer 4

replace \(x\) by \(t+1\)

Answer 5

would it be: 1 / abs. value of t + 1 * sqr root of (t+1)^2 -1

Answer 6

or ( t + 1)^4 -1