The chitauritwo is plying past Hawkeye who is stationed on top of a building. The trajectory of the chitauritwo is given by the equations

xc = -100m + 1ms-1t + ½(0.1)t2
yc = 100m
zc = 440m
Hawkeye’s position is given by xc = 0, yc = 0, and zc = 440m. if he is to fire an arrow with an initial velocity of 137m/s at time t=0, will he be able to shoot the chitauritwo? In what direction should he fire his arrow? Ignore air resistance, because the arrow is so fast, and note that the gravity acts in the negative z-direction.

Question

The chitauritwo is plying past Hawkeye who is stationed on top of a building. The trajectory of the chitauritwo is given by the equations

xc = -100m + 1ms-1t + ½(0.1)t2
yc = 100m
zc = 440m
Hawkeye’s position is given by xc = 0, yc = 0, and zc = 440m. if he is to fire an arrow with an initial velocity of 137m/s at time t=0, will he be able to shoot the chitauritwo? In what direction should he fire his arrow? Ignore air resistance, because the arrow is so fast, and note that the gravity acts in the negative z-direction.