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Mathematics 17 Online
OpenStudy (anonymous):

Use the trig ratios to find the value of x. Round to the nearest tenth.

OpenStudy (anonymous):

OpenStudy (anonymous):

sorry its sideways

zepdrix (zepdrix):

|dw:1361921939717:dw|So it looks like they've provided us with the length of the hypotenuse. And we need to solve for the side OPPOSITE our angle.

OpenStudy (anonymous):

so would it be x/17 which is sin

zepdrix (zepdrix):

\[\large \sin 61^o=\frac{x}{17}\]Yes, very good. And from here, we need to solve for x.

OpenStudy (anonymous):

so would the answer be 14.9 (rounded to the tenth)

zepdrix (zepdrix):

yup sounds good.

OpenStudy (anonymous):

How would you do number 14

OpenStudy (anonymous):

since we don't have the hypotenuse

zepdrix (zepdrix):

Hmm so we're given the length of the side `adjacent` to our known angle. And we need to solve for the side `opposite` this same angle. Hmmmmm, which trig function? c:

OpenStudy (anonymous):

tan?

OpenStudy (anonymous):

9/x

zepdrix (zepdrix):

yes tan, i think it's x/9 though.

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

9*tan(25)=4.2

zepdrix (zepdrix):

ok good job c:

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