Question

Put in vertex form and identify vertex h(x)=5x^2-20x+9

Answer 1

@jim_thompson5910
@Directrix
want to take over, sorry i have mid-terms tomorrow (need to study)

Answer 2

okay

Answer 3

@ghazi
@Cha1234
@UnkleRhaukus

Answer 4

h(x)=5x^2-20x+9

h(x) - 9=5x^2-20x

h(x) - 9=5(x^2-4x)

h(x) - 9=5(x^2-4x + 4 - 4)

h(x) - 9=5(x^2-4x + 4) - 5*4

h(x) - 9=5(x^2-4x + 4) - 20

h(x) - 9=5(x-2)^2 - 20

h(x)=5(x-2)^2 - 20+9

h(x)=5(x-2)^2 - 11

The equation is now in vertex form f(x) = a(x-h)^2+k where

a = 5
h = 2
k = -11

so the vertex is (2, -11)

Answer 5

thank you!!!

Answer 6

np