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I need calculus help. Find the differential of the function y=x3sin(6x). i found that to be 2sec^2(x) which is correct. next i need to Evaluate dy and Δy when x=π/4 and dx=−0.2 what is dy: and Δy:
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\[\large y=x^3 \sin(6x)\]Applying the product rule gives us, \[\large dy=\left[3x^2\sin(6x)+6x^3\cos(6x)\right]dx\] Hmm I don't quite understand how you got to 2sec^2(x).
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