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in the second quadrant of a unit circle, sin=1/3, what is sec=?
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sin = opposite side / hypotenuse sin = 1 /3 opposite side / hypotenuse = 1 / 3 opposite side = 1 hypotenuse = 3 |dw:1361941407395:dw|
adjacent side = x opposite side = y hypotenuse = h x^2 + y^2 = h^2 x^2 + (1)^2 = (3)^2 x^2 + 1 = 9 x^2 = 8 x = sqrt(8) sec = hypotenuse / adjacent sec = 3 / sqrt(8) sec = 3sqrt(8) / 8 sec = 3 2sqrt(2) / 8 sec = 3sqrt(2)/4
Since this is in the second quadrant, your adjacent side should be flipped. So adjacent will have a negative value, and sec = -3sqrt(2)/4|dw:1361941685222:dw|
THANKS! and the sec would be?
*tan
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tan = opposite / adjacent
Thanks!!!!!
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