Question

Need help solving this small problem. For some reason i'm having a brain fart.

Answer 1

drawing equation sec

Answer 2

\[\frac{ X^4-81 }{ x-3 }\]

Answer 3

factor as the difference of two squares twice

Answer 4

\[x^4-81=(x^2+9)(x^2-9)=(x^2+9)(x+3)(x-3)\] then cancel

Answer 5

Alright that makes this easier ty