Question

Factor 2(x+4)(x-3)^3+(x+4)^2*4(x-3)^2 for me with steps please. I know the solution but I donnot know the steps and I can't solve it by my own. MEDAL will be given and a GREAT FAN TESTIMONIAL too.

Answer 1

We can't work out the entire problem for you, as It's against the CoC, and that appears to be what you're after. Have you at least attempted it yourself, where you can show us you tried?

Answer 2

yeah

Answer 3

I tried to expand the solution: 2(x+4)(x-3)^2(3x+5) but no avail

Answer 4

factor by group. Basically means you put the first two term in one group and the last two term in one group

notice the third term is a negative number. You need to include the negative in the parethesis

(x^3 - 4x^2) + (-x + 4)

take oug GCF of each binomial
x^2 (x - 4) + -1(x - 4)

negative and positve becomes negative
x^2 (x - 4) - 1(x - 4)

take out x - 4
(x - 4) (x^2 - 1)

notice that x^2 - 1 can also be factored further. It is a difference of perfect square. Use this formula
a^2 - b^2 = (a - b) (a + b)


i hope this is right

Answer 5

The solution that is written on my test is 2(x+4)(x-3)^2(3x+5)

Answer 6

i gave u an example

Answer 7

so u can follow it and learn

Answer 8

What do you mean by "take oug GCF of each binomial" I am not so good on math terms in english, so if I take out "CGF" from each "binomial" x^2 (x - 4) + -1(x - 4) How it should be once done?

Answer 9

Please if someone could solve my problem using steps so I can learn I would be deeply thankful

Answer 10

Greatest Comman Factor thats what GCF mean

Answer 11

Well a binomial is a mathematical expression with two terms.

ex. (2x+5) {2x is one term 5 is the other}, (5x+9) {5x is one term 9 is the other}

terms are seperated by + or - signs only.

Answer 12

whatsthe GCF in this x^2 (x - 4) + -1(x - 4)

Answer 13

2(x+4

Answer 14

but thats not even in the line x^2 (x - 4) + -1(x - 4) how did you come up to that?

Answer 15

thinking outside the box lol

Answer 16

jk

Answer 17

it should be -1(x-4)

Answer 18

wait now i got it

Answer 19

ok

Answer 20

I wait

Answer 21

whats that...?

Answer 22

lol the question that u asked me so i put the answer in the big box

Answer 23

I see, why is it called GCF instead of just Factor? what's the difference?

Answer 24

the greatst command facter is like a + sign but just the facter it could be both

Answer 25

Ok. To Others: If someone can solve my problem with steps as stated in the first post It would be really helpful to me.

Answer 26

oh sorry if im not very helpful

Answer 27

):

Answer 28

You were helpful to me, thanks a lot :)

Answer 29

i dont feel like i help u

Answer 30

In the end, if noone is gonna show me the steps that I need, I am gonna study that generic example of group Factoring which you gave me, and hopefully one day I will be able to understand, so yea you helped me :)

Answer 31

im telling u it really dont feel like it but ok

Answer 32

(:

Answer 33

Alright thank you anyways then :) . PS: I Still need Help!

Answer 34

I STILL NEED HELP PLEASE READ THE TOPIC PLEASE

Answer 35

so if you expand \[2 (x+4) (x-3)^3+(x+4)^2×4 (x-3)^2\]
it should be \[6 x^4-2 x^3-110 x^2+66 x+360\]
DO YOU NEED A WLAKTHROUGH ON THAT?

Answer 36

\[2 (x+4) (x-3)^3+(x+4)^2×4 (x-3)^2\]
has three roots or solutions.

Answer 37

DO YOU NEED A WLAKTHROUGH ON THAT? Yes please.

Answer 38

So what if it has 3 roots/solutions? Why did you mention this?

Answer 39

well that is if you want to find its roots.
like x = ?
do u get me?

Answer 40

Yea got it however I only wish to factor this one

Answer 41

\[2 (x+4) (x-3)^3+(x+4)^2×4 (x-3)^2\]
do you know how to start off?

Answer 42

It gets to 6x4−2x3−110x2+66x+360 right?

Answer 43

well that is the expanded form. so i dont think so.

Answer 44

:( can you guide me friend please? :(

Answer 45

Guide me please? I am lost?