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Mathematics 16 Online
OpenStudy (anonymous):

Factor..... 14x^2+3x-5

OpenStudy (anonymous):

@jim_thompson5910 Can you please help me?

jimthompson5910 (jim_thompson5910):

multiply 14 and -5 to get -70 then list all the possible ways to multiply to -70 -70 = -1*70 -70 = -2*35 .... etc etc Which pair of factors would also add to 3?

OpenStudy (anonymous):

10 and -7 @jim_thompson5910

jimthompson5910 (jim_thompson5910):

good, so you can break up 3x into 10x - 7x to get 14x^2+10x-7x-5

jimthompson5910 (jim_thompson5910):

now factor by grouping

OpenStudy (anonymous):

(3x+10)(3x-7) @jim_thompson5910

jimthompson5910 (jim_thompson5910):

not qute

jimthompson5910 (jim_thompson5910):

quite*

jimthompson5910 (jim_thompson5910):

14x^2+3x-5 14x^2+10x-7x-5 (14x^2+10x)+(-7x-5) 2x(7x+5)+(-7x-5) 2x(7x+5)-1(7x+5) (2x-1)(7x+5) -------------------- 14x^2+3x-5 completely factors to (2x-1)(7x+5)

OpenStudy (anonymous):

oh wow ok i understand you thank you very much @jim_thompson5910

jimthompson5910 (jim_thompson5910):

ok great

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